相思资源网 Design By www.200059.com
核心代码：
复制代码 代码如下:
$("#result").text(isOverlap("one","two")+","+isOverlap("one","three")+","+isOverlap("two","three"));
function isOverlap(idOne,idTwo){
var objOne=$("#"+idOne),
objTwo=$("#"+idTwo),
offsetOne = objOne.offset(),
offsetTwo = objTwo.offset(),
topOne=offsetOne.top,
topTwo=offsetTwo.top,
leftOne=offsetOne.left,
leftTwo=offsetTwo.left,
widthOne = objOne.width(),
widthTwo = objTwo.width(),
heightOne = objOne.height(),
heightTwo = objTwo.height();
var leftTop = leftTwo > leftOne && leftTwo < leftOne+widthOne
&& topTwo > topOne && topTwo < topOne+heightOne,
rightTop = leftTwo+widthTwo > leftOne && leftTwo+widthTwo < leftOne+widthOne
&& topTwo > topOne && topTwo < topOne+heightOne,
leftBottom = leftTwo > leftOne && leftTwo < leftOne+widthOne
&& topTwo+heightTwo > topOne && topTwo+heightTwo < topOne+heightOne,
rightBottom = leftTwo+widthTwo > leftOne && leftTwo+widthTwo < leftOne+widthOne
&& topTwo+heightTwo > topOne && topTwo+heightTwo < topOne+heightOne;
return leftTop || rightTop || leftBottom || rightBottom;
}
原理很简单，就是判断一个元素的四个点是否在另一个元素内部。
完整演示代码：
复制代码 代码如下:
JSCode
LoginResult JavaScript HTML CSS ALL Edit Share
$("#result").text(isOverlap("one","two")+","+isOverlap("one","three")+","+isOverlap("two","three"));
function isOverlap(idOne,idTwo){
var objOne=$("#"+idOne),
objTwo=$("#"+idTwo),
offsetOne = objOne.offset(),
offsetTwo = objTwo.offset(),
topOne=offsetOne.top,
topTwo=offsetTwo.top,
leftOne=offsetOne.left,
leftTwo=offsetTwo.left,
widthOne = objOne.width(),
widthTwo = objTwo.width(),
heightOne = objOne.height(),
heightTwo = objTwo.height();
var leftTop = leftTwo > leftOne && leftTwo < leftOne+widthOne
&& topTwo > topOne && topTwo < topOne+heightOne,
rightTop = leftTwo+widthTwo > leftOne && leftTwo+widthTwo < leftOne+widthOne
&& topTwo > topOne && topTwo < topOne+heightOne,
leftBottom = leftTwo > leftOne && leftTwo < leftOne+widthOne
&& topTwo+heightTwo > topOne && topTwo+heightTwo < topOne+heightOne,
rightBottom = leftTwo+widthTwo > leftOne && leftTwo+widthTwo < leftOne+widthOne
&& topTwo+heightTwo > topOne && topTwo+heightTwo < topOne+heightOne;
return leftTop || rightTop || leftBottom || rightBottom;
}
<div id="one">One</div>
<div id="two">Two</div>
<div id="three">Three</div>
<h1 id="result"></h1>
div{
width:200px;
height:200px;
background:#EEE;
}
#two{
position:absolute;
left:100px;
top:50px;
background:#F60;
}
DownLoad
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8"/>
<title>JSCode demo</title>
<style type="text/css">
div{
width:200px;
height:200px;
background:#EEE;
}
#two{
position:absolute;
left:100px;
top:50px;
background:#F60;
}
</style>
<script src="/UploadFiles/2021-04-02/jQuery-1.7.2.js"></head>
<body>
<div id="one">One</div>
<div id="two">Two</div>
<div id="three">Three</div>
<h1 id="result"></h1>
<script type="text/javascript">
$("#result").text(isOverlap("one","two")+","+isOverlap("one","three")+","+isOverlap("two","three"));
function isOverlap(idOne,idTwo){
var objOne=$("#"+idOne),
objTwo=$("#"+idTwo),
offsetOne = objOne.offset(),
offsetTwo = objTwo.offset(),
topOne=offsetOne.top,
topTwo=offsetTwo.top,
leftOne=offsetOne.left,
leftTwo=offsetTwo.left,
widthOne = objOne.width(),
widthTwo = objTwo.width(),
heightOne = objOne.height(),
heightTwo = objTwo.height();
var leftTop = leftTwo > leftOne && leftTwo < leftOne+widthOne
&& topTwo > topOne && topTwo < topOne+heightOne,
rightTop = leftTwo+widthTwo > leftOne && leftTwo+widthTwo < leftOne+widthOne
&& topTwo > topOne && topTwo < topOne+heightOne,
leftBottom = leftTwo > leftOne && leftTwo < leftOne+widthOne
&& topTwo+heightTwo > topOne && topTwo+heightTwo < topOne+heightOne,
rightBottom = leftTwo+widthTwo > leftOne && leftTwo+widthTwo < leftOne+widthOne
&& topTwo+heightTwo > topOne && topTwo+heightTwo < topOne+heightOne;
return leftTop || rightTop || leftBottom || rightBottom;
}
</script>
</body>
</html>
Share link
Embed on your page
Share on Sina
Share on QQ
作者：Artwl
复制代码 代码如下:
$("#result").text(isOverlap("one","two")+","+isOverlap("one","three")+","+isOverlap("two","three"));
function isOverlap(idOne,idTwo){
var objOne=$("#"+idOne),
objTwo=$("#"+idTwo),
offsetOne = objOne.offset(),
offsetTwo = objTwo.offset(),
topOne=offsetOne.top,
topTwo=offsetTwo.top,
leftOne=offsetOne.left,
leftTwo=offsetTwo.left,
widthOne = objOne.width(),
widthTwo = objTwo.width(),
heightOne = objOne.height(),
heightTwo = objTwo.height();
var leftTop = leftTwo > leftOne && leftTwo < leftOne+widthOne
&& topTwo > topOne && topTwo < topOne+heightOne,
rightTop = leftTwo+widthTwo > leftOne && leftTwo+widthTwo < leftOne+widthOne
&& topTwo > topOne && topTwo < topOne+heightOne,
leftBottom = leftTwo > leftOne && leftTwo < leftOne+widthOne
&& topTwo+heightTwo > topOne && topTwo+heightTwo < topOne+heightOne,
rightBottom = leftTwo+widthTwo > leftOne && leftTwo+widthTwo < leftOne+widthOne
&& topTwo+heightTwo > topOne && topTwo+heightTwo < topOne+heightOne;
return leftTop || rightTop || leftBottom || rightBottom;
}
原理很简单，就是判断一个元素的四个点是否在另一个元素内部。
完整演示代码：
复制代码 代码如下:
JSCode
LoginResult JavaScript HTML CSS ALL Edit Share
$("#result").text(isOverlap("one","two")+","+isOverlap("one","three")+","+isOverlap("two","three"));
function isOverlap(idOne,idTwo){
var objOne=$("#"+idOne),
objTwo=$("#"+idTwo),
offsetOne = objOne.offset(),
offsetTwo = objTwo.offset(),
topOne=offsetOne.top,
topTwo=offsetTwo.top,
leftOne=offsetOne.left,
leftTwo=offsetTwo.left,
widthOne = objOne.width(),
widthTwo = objTwo.width(),
heightOne = objOne.height(),
heightTwo = objTwo.height();
var leftTop = leftTwo > leftOne && leftTwo < leftOne+widthOne
&& topTwo > topOne && topTwo < topOne+heightOne,
rightTop = leftTwo+widthTwo > leftOne && leftTwo+widthTwo < leftOne+widthOne
&& topTwo > topOne && topTwo < topOne+heightOne,
leftBottom = leftTwo > leftOne && leftTwo < leftOne+widthOne
&& topTwo+heightTwo > topOne && topTwo+heightTwo < topOne+heightOne,
rightBottom = leftTwo+widthTwo > leftOne && leftTwo+widthTwo < leftOne+widthOne
&& topTwo+heightTwo > topOne && topTwo+heightTwo < topOne+heightOne;
return leftTop || rightTop || leftBottom || rightBottom;
}
<div id="one">One</div>
<div id="two">Two</div>
<div id="three">Three</div>
<h1 id="result"></h1>
div{
width:200px;
height:200px;
background:#EEE;
}
#two{
position:absolute;
left:100px;
top:50px;
background:#F60;
}
DownLoad
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8"/>
<title>JSCode demo</title>
<style type="text/css">
div{
width:200px;
height:200px;
background:#EEE;
}
#two{
position:absolute;
left:100px;
top:50px;
background:#F60;
}
</style>
<script src="/UploadFiles/2021-04-02/jQuery-1.7.2.js"></head>
<body>
<div id="one">One</div>
<div id="two">Two</div>
<div id="three">Three</div>
<h1 id="result"></h1>
<script type="text/javascript">
$("#result").text(isOverlap("one","two")+","+isOverlap("one","three")+","+isOverlap("two","three"));
function isOverlap(idOne,idTwo){
var objOne=$("#"+idOne),
objTwo=$("#"+idTwo),
offsetOne = objOne.offset(),
offsetTwo = objTwo.offset(),
topOne=offsetOne.top,
topTwo=offsetTwo.top,
leftOne=offsetOne.left,
leftTwo=offsetTwo.left,
widthOne = objOne.width(),
widthTwo = objTwo.width(),
heightOne = objOne.height(),
heightTwo = objTwo.height();
var leftTop = leftTwo > leftOne && leftTwo < leftOne+widthOne
&& topTwo > topOne && topTwo < topOne+heightOne,
rightTop = leftTwo+widthTwo > leftOne && leftTwo+widthTwo < leftOne+widthOne
&& topTwo > topOne && topTwo < topOne+heightOne,
leftBottom = leftTwo > leftOne && leftTwo < leftOne+widthOne
&& topTwo+heightTwo > topOne && topTwo+heightTwo < topOne+heightOne,
rightBottom = leftTwo+widthTwo > leftOne && leftTwo+widthTwo < leftOne+widthOne
&& topTwo+heightTwo > topOne && topTwo+heightTwo < topOne+heightOne;
return leftTop || rightTop || leftBottom || rightBottom;
}
</script>
</body>
</html>
Share link
Embed on your page
Share on Sina
Share on QQ
作者：Artwl
标签：
元素,重叠
相思资源网 Design By www.200059.com
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免责声明：本站文章均来自网站采集或用户投稿，网站不提供任何软件下载或自行开发的软件！ 如有用户或公司发现本站内容信息存在侵权行为，请邮件告知！ 858582#qq.com
相思资源网 Design By www.200059.com
暂无基于jQuery判断两个元素是否有重叠部分的代码的评论...
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这一波大模型产业落地浪潮里，不少企业其实处在 “干瞪眼“的状态。
一种情况是，很多大模型产品看得见却摸不着，在台上一个个遥遥领先——今天Sora技精四座，明天英伟达的机器人又赢得满堂彩，可是到了台下一问：啥时候能用上啊？答曰：遥遥无期。
另一种情况是，企业想用上大模型，却又难免瞻前顾后——既要考虑场景融合，又得兼顾安全性，还要考虑打通现有系统，再加上各种部署成本和繁琐的采购流程……最后只能拂袖：罢了，再等等吧。
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