几行代码轻松搞定jquery实现flash8类似的连接效果

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很简单几行代码就可以实现整个页面的连接效果.
复制代码代码如下:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=gb2312" />
<script src="/UploadFiles/2021-04-02/jquery-latest.pack.js"><script type="text/javascript">
$(document).ready(function(){
   $("#list1").css("list-style","none");
  $("#list1").css("margin","0px");
  $("#list1").children().css("background-image","url(l_04.gif)");
  $("#list1").children().css("height","30px");
  $("#list1").children().children().css("margin-left","0px");
  $("#list1").children().children().css("padding-left","12px");
  $("#list1").children().children().css("background-image","url(allow_01.gif)");
  $("#list1").children().children().css("background-repeat","no-repeat");
  $("#list1").children().children().css("background-position","left center");
  $("#list1").children().children().mouseover(function(){
   $(this).css("background-image","url(allow_02.gif)");
   $(this).css("margin-left","6px");
  });
  $("#list1").children().children().mouseout(function(){
   $(this).css("background-image","url(allow_01.gif)");
   $(this).css("margin-left","0px");
  });
}
);
</script>
<title>无标题文档</title>
</head>
<body>
<div>
<ul id="list1">
  <li><a href="#">例表第一项</a></li>
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  <li><a href="#">例表第一项</a></li>
  <li><a href="#">例表第一项</a></li>
  <li><a href="#">例表第一项</a></li>
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  <li><a href="#">例表第一项</a></li>
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</ul>
</div>
</body>
</html>

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