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PHP 实现公历日期与农历日期的互转换
前言:
今天根据客户的需求对时间进行了转换,就是客户要求增加农历日期的显示,在网上抄袭了一段,稍微修改了一下运行成功了,不难的,改动的很少的.
示例代码:
<"零","一","二","三","四","五","六","七","八","九");
for($i=0;$i<4;$i++)
for($k=0;$k<10;$k++)
if($year[$i]==$k)
$tmp.=$Name[$k];
return $tmp;
}
private function LMonName($month)
{
if($month >=1 && $month <=12 )
{
$Name = array( 1=>"正","二","三","四","五","六","七","八","九","十","十一","十二");
return $Name[$month];
}
return $month;
}
private function LDayName($day)
{
if($day >=1 && $day <=30 )
{
$Name = array( 1 =>
"初一","初二","初三","初四","初五","初六","初七","初八","初九","初十",
"十一","十二","十三","十四","十五","十六","十七","十八","十九","二十",
"廿一","廿二","廿三","廿四","廿五","廿六","廿七","廿八","廿九","三十"
);
return $Name[$day];
}
return $day;
}
//公历转农历(Sdate:公历日期)
public function S2L($date)
{
list($year, $month, $day) = explode("-", $date);
if($year <= 1951 || $month <= 0 || $day <= 0 || $year >= 2051 ) return false;
//获取查询日期到当年1月1日的天数
$date1 = strtotime($year."-01-01");//当年1月1日
$date2 = strtotime($year."-".$month."-".$day);
$days=round(($date2-$date1)/3600/24);
$days += 1;
//获取相应年度农历数据,化成数组Larray
$Larray = $this->_LMDay[$year - $this->_LStart];
if($days <= $Larray[0])
{
$Lyear = $year - 1;
$days = $Larray[0] - $days;
$Larray = $this->_LMDay[$Lyear - $this->_LStart];
if($days < $Larray[12])
{
$Lmonth = 12;
$Lday = $Larray[12] - $days;
}
else
{
$Lmonth = 11;
$days = $days - $Larray[12];
$Lday = $Larray[11] - $days;
}
}
else
{
$Lyear = $year;
$days = $days - $Larray[0];
for($i = 1;$i <= 12;$i++)
{
if($days > $Larray[$i]) $days = $days - $Larray[$i];
else
{
if ($days > 30){
$days = $days - $Larray[13];
$Ltype = 1;
}
$Lmonth = $i;
$Lday = $days;
break;
}
}
}
return mktime(0, 0, 0, $Lmonth, $Lday, $Lyear);
//$Ldate = $Lyear."-".$Lmonth."-".$Lday;
//$Ldate = $this->LYearName($Lyear)."年".$this->LMonName($Lmonth)."月".$this->LDayName($Lday);
//if($Ltype) $Ldate.="(闰)";
//return $Ldate;
}
//农历转公历(date:农历日期; type:是否闰月)
public function L2S($date,$type = 0)
{
list($year, $month, $day) = split("-",$date);
if($year <= 1951 || $month <= 0 || $day <= 0 || $year >= 2051 ) return false;
$Larray = $this->_LMDay[$year - $this->_LStart];
if($type == 1 && count($Larray)<=12 ) return false;//要求查询闰,但查无闰月
//如果查询的农历是闰月并该年度农历数组存在闰月数据就获取
if($Larray[$month]>30 && $type == 1 && count($Larray) >=13) $day = $Larray[13] + $day;
//获取该年农历日期到公历1月1日的天数
$days = $day;
for($i=0;$i<=$month-1;$i++)
$days += $Larray[$i];
//当查询农历日期距离公历1月1日超过一年时
if($days > 366 || ($this->GetSMon($month,2)!=29 && $days>365 ))
{
$Syear = $year +1;
if($this->GetSMon($month,2)!=29)
$days-=366;
else
$days-=365;
if($days > $this->_SMDay[1])
{
$Smonth = 2;
$Sday = $days - $this->_SMDay[1];
}
else
{
$Smonth = 1;
$Sday = $days;
}
}
else
{
$Syear =$year;
for($i=1;$i<=12;$i++)
{
if($days > $this->GetSMon($Syear,$i))
$days-=$this->GetSMon($Syear,$i);
else
{
$Smonth = $i;
$Sday = $days;
break;
}
}
}
return mktime(0, 0, 0, $Smonth, $Sday, $Syear);
//$Sdate = $Syear."-".$Smonth."-".$Sday;
//return $Sdate;
}
}
"htmlcode">
//公历转农历
require_once(CORE_."Lunar.php"); // 加载lunar.php文件
$today = date("Y-m-d");
$lunar = new Lunar(); // 实例化类
$nonglitime = array();
$nl = date("Y-n-d",$lunar->S2L($today));
echo $nl;exit; // 转为农历是:2012-05-25
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