相思资源网 Design By www.200059.com
1
MySQL中如何实现以下SQL查询
(SELECT S.Name
FROM STUDENT S, TRANSCRIPT T
WHERE S.StudId = T.StudId AND T.CrsCode = 'CS305')
INTERSECT
(SELECT S.Name
FROM STUDENT S, TRANSCRIPT T
WHERE S.StudId = T.StudId AND T.CrsCode = 'CS315')
请各位不吝赐教,小弟先谢过~
解:
取交集
select a.* from
(
SELECT S.Name
FROM STUDENT S, TRANSCRIPT T
WHERE S.StudId = T.StudId AND T.CrsCode = 'CS305'
) as a
cross join
(
SELECT S.Name
FROM STUDENT S, TRANSCRIPT T
WHERE S.StudId = T.StudId AND T.CrsCode = 'CS315'
) as b on a.Name = b.Name;

2.
SELECT * FROM (
SELECT DISTINCT col1 FROM t1 WHERE...
UNION ALL
SELECT DISTINCT col1 FROM t1 WHERE...
) AS tbl
GROUP BY tbl.col1 HAVING COUNT(*) = 2

3.
交集:
SELECT * FROM table1 AS a JOIN table2 AS b ON a.name =b.name
举例:
表a:
FieldA
001
002
003
表b:
FieldA
001
002
003
004
请教如何才能得出以下结果集,即表A, B行交集
FieldA
001
002
003
答案:select a.FieldA from a inner join b on a.FieldA=b.FieldA
差集:
NOT IN 表示差集
SELECT * FROM table1 WHERE name NOT IN (SELECT name FROM table2)
标签:
MySQL,交集,实现

相思资源网 Design By www.200059.com
广告合作:本站广告合作请联系QQ:858582 申请时备注:广告合作(否则不回)
免责声明:本站文章均来自网站采集或用户投稿,网站不提供任何软件下载或自行开发的软件! 如有用户或公司发现本站内容信息存在侵权行为,请邮件告知! 858582#qq.com
相思资源网 Design By www.200059.com

评论“MySQL 查询结果取交集的实现方法”

暂无MySQL 查询结果取交集的实现方法的评论...